# Line slope calculator 3x+5y=26

**Straight line given by points A[2; 4] and B[7; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.6x+5.2

**Canonical form of the line equation:**3x+5y-26 = 0

**Parametric form of the line equation:**

x = 5t+2

y = -3t+4 ; t ∈ R

**Slope:**m = -0.6

**Slope angle of line: φ =**-30°57'50″ = -0.5404 rad

**X intercept:**x

_{0}= 8.6667

**Y intercept:**y

_{0}= q = 5.2

**Distance line from the origin:**d

_{0}= 4.459

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; -3)

**Normal vector: n =**(3; 5)

**Midpoint of the segment AB: M =**[4.5; 2.5]

**Perpendicular Bisector equation:**5x-3y-15 = 0

**Vector OA = (2; 4) ; |OA| = 4.4721**

**Vector OB = (7; 1) ; |OB| = 7.0711**

**Scalar product OA .OB = 18**

**Angle ∠ AOB = 55°18'17″ = 0.9653 rad**